PHP: Finding if someone is under 13 years of age..

[Tristan Perry]

Hello,
I am working on a project, and the registration must comply with the COPPA law. I'm trying to work out if an age is under 13 from a date of birth.. I have the fields: year, month and day on the registration form. From this, how can I find out the age? I've tried a few things but none of them work..
I'd appreciate any help,
Thanks.

[[Unknown]]

Compile them together into a timestamp (using, for example, mktime()...), and then do time() - 13 * 365 * 24 * 3600 or so.

-[Unknown]

[Tristan Perry]

Compile them together into a timestamp (using, for example, mktime()...), and then do time() - 13 * 365 * 24 * 3600 or so.

-[Unknown]

Thanks, although I'm still not getting this. I can understand the kind of thing I have to do, although I can't seem to make this work.. What am I doing wrong?

Code Select Expand

<?php
$dob1 = 1990; // Year
$dob2 = 04; // Month
$dob3 = 14; // Day

$dob = mktime(0,0,0,$dob2,$dob3,$dob1);
$compare = time() - 13 * 365 * 24 * 3600;

// This is just to see if I'm doing the correct thing
echo $compare.'<br />'.$dob;
?>

Using the above I come up with something like:

697716062
640069200

(= 57646862)

[[Unknown]]

Righto.  The compare number represents 13 years ago.... and the other number represents their birthdate.

Because the second number ($dob) is lower than the first number (13 years ago) that means they're older than 13!

-[Unknown]

[Tristan Perry]

Righto.  The compare number represents 13 years ago.... and the other number represents their birthdate.

Because the second number ($dob) is lower than the first number (13 years ago) that means they're older than 13!

-[Unknown]

Ah right!  Thanks a lot, you've been a great help! I was thinking after doing the mktime() thing, I'd take the first number away from the second to find the age or something like that!

[[Unknown]]

Actually, that could work too.  You could do today's date minus 13 years... e.g. 20050206 - 130000.  That would be thirteen years ago.  Then, you could take their date, concatenate it together like that, and compare (YYYYMMDD.)

-[Unknown]

[Tristan Perry]

Actually, that could work too.  You could do today's date minus 13 years... e.g. 20050206 - 130000.  That would be thirteen years ago.  Then, you could take their date, concatenate it together like that, and compare (YYYYMMDD.)

-[Unknown]

Yeah that's what I tried firstly but I got confused! I think I'll stick to the first method 

[SeaOfSin]

Does anyone know if this was completed, I'm looking for something similar!!!!! All I have is this to work with :-

Compile them together into a timestamp (using, for example, mktime()...), and then do time() - 13 * 365 * 24 * 3600 or so.

-[Unknown]

Thanks, although I'm still not getting this. I can understand the kind of thing I have to do, although I can't seem to make this work.. What am I doing wrong?

Code Select Expand

<?php
$dob1 = 1990; // Year
$dob2 = 04; // Month
$dob3 = 14; // Day

$dob = mktime(0,0,0,$dob2,$dob3,$dob1);
$compare = time() - 13 * 365 * 24 * 3600;

// This is just to see if I'm doing the correct thing
echo $compare.'<br />'.$dob;
?>

Using the above I come up with something like:

697716062
640069200

(= 57646862)

I'm not sure how to finish it!

Thanks

Sea Of Sin

[bloc]

You need to convert that to actual years. Try using

Code Select Expand

    echo date("Y",$compare);